Base | Representation |
---|---|
bin | 110000100010001101… |
… | …000000110111101111 |
3 | 11222111212122021012222 |
4 | 300202031000313233 |
5 | 1323212020204320 |
6 | 35535055545555 |
7 | 3523263653021 |
oct | 604215006757 |
9 | 158455567188 |
10 | 52113444335 |
11 | 20112754067 |
12 | a12482b2bb |
13 | 4bb68870c4 |
14 | 27452ba011 |
15 | 15501b5825 |
hex | c22340def |
52113444335 has 4 divisors (see below), whose sum is σ = 62536133208. Its totient is φ = 41690755464.
The previous prime is 52113444329. The next prime is 52113444343. The reversal of 52113444335 is 53344431125.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 52113444335 - 210 = 52113443311 is a prime.
It is a super-2 number, since 2×521134443352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 52113444295 and 52113444304.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5211344429 + ... + 5211344438.
It is an arithmetic number, because the mean of its divisors is an integer number (15634033302).
Almost surely, 252113444335 is an apocalyptic number.
52113444335 is a deficient number, since it is larger than the sum of its proper divisors (10422688873).
52113444335 is a wasteful number, since it uses less digits than its factorization.
52113444335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10422688872.
The product of its digits is 86400, while the sum is 35.
The spelling of 52113444335 in words is "fifty-two billion, one hundred thirteen million, four hundred forty-four thousand, three hundred thirty-five".
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