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52300113 = 332295399
BaseRepresentation
bin1100011110000…
…0100101010001
310122102010021020
43013200211101
5101342100423
65104550053
71203354315
oct307404521
9118363236
1052300113
1127581938
1215622329
13aab2318
146d35b45
1548d14e3
hex31e0951

52300113 has 8 divisors (see below), whose sum is σ = 69768000. Its totient is φ = 34849488.

The previous prime is 52300111. The next prime is 52300121. The reversal of 52300113 is 31100325.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 52300113 - 21 = 52300111 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 52300092 and 52300101.

It is not an unprimeable number, because it can be changed into a prime (52300111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6988 + ... + 12386.

It is an arithmetic number, because the mean of its divisors is an integer number (8721000).

Almost surely, 252300113 is an apocalyptic number.

It is an amenable number.

52300113 is a deficient number, since it is larger than the sum of its proper divisors (17467887).

52300113 is a wasteful number, since it uses less digits than its factorization.

52300113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8631.

The product of its (nonzero) digits is 90, while the sum is 15.

The square root of 52300113 is about 7231.8817053378. The cubic root of 52300113 is about 373.9677996623.

Adding to 52300113 its reverse (31100325), we get a palindrome (83400438).

The spelling of 52300113 in words is "fifty-two million, three hundred thousand, one hundred thirteen".

Divisors: 1 3 3229 5399 9687 16197 17433371 52300113