Base | Representation |
---|---|
bin | 10111110101010111010101… |
… | …11110001010110010000001 |
3 | 20212120110021222111010212221 |
4 | 23322223222332022302001 |
5 | 23332201000034031200 |
6 | 303245201523451041 |
7 | 14016402510623044 |
oct | 1372535276126201 |
9 | 225513258433787 |
10 | 52411133111425 |
11 | 15777489316700 |
12 | 5a65766526a81 |
13 | 233246bc87a7a |
14 | cd29d8a9ac5b |
15 | 60d501b1a91a |
hex | 2faaeaf8ac81 |
52411133111425 has 72 divisors (see below), whose sum is σ = 75213847950080. Its totient is φ = 36101880144000.
The previous prime is 52411133111399. The next prime is 52411133111443.
52411133111425 is nontrivially palindromic in base 10.
52411133111425 is digitally balanced in base 6, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 52411133111425 - 29 = 52411133110913 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 230993584 + ... + 231220366.
Almost surely, 252411133111425 is an apocalyptic number.
52411133111425 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
52411133111425 is a deficient number, since it is larger than the sum of its proper divisors (22802714838655).
52411133111425 is a wasteful number, since it uses less digits than its factorization.
52411133111425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 230855 (or 230839 counting only the distinct ones).
The product of its digits is 14400, while the sum is 34.
It can be divided in two parts, 5241113 and 3111425, that added together give a palindrome (8352538).
The spelling of 52411133111425 in words is "fifty-two trillion, four hundred eleven billion, one hundred thirty-three million, one hundred eleven thousand, four hundred twenty-five".
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