Base | Representation |
---|---|
bin | 100110001101001101100… |
… | …1110101000110011010111 |
3 | 200120222220000011001221112 |
4 | 1030122123032220303113 |
5 | 1142013124402410320 |
6 | 15100145010205235 |
7 | 1051243010311265 |
oct | 114323316506327 |
9 | 20528800131845 |
10 | 5251054341335 |
11 | 1744a6130aa90 |
12 | 70983358381b |
13 | 2c123170876a |
14 | 14221c20d435 |
15 | 918d2da2ec5 |
hex | 4c69b3a8cd7 |
5251054341335 has 16 divisors (see below), whose sum is σ = 6926581613952. Its totient is φ = 3789796327200.
The previous prime is 5251054341319. The next prime is 5251054341341. The reversal of 5251054341335 is 5331434501525.
It is not a de Polignac number, because 5251054341335 - 24 = 5251054341319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5251054341292 and 5251054341301.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 364396289 + ... + 364410698.
It is an arithmetic number, because the mean of its divisors is an integer number (432911350872).
Almost surely, 25251054341335 is an apocalyptic number.
5251054341335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5251054341335 is a deficient number, since it is larger than the sum of its proper divisors (1675527272617).
5251054341335 is a wasteful number, since it uses less digits than its factorization.
5251054341335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 728807134.
The product of its (nonzero) digits is 540000, while the sum is 41.
The spelling of 5251054341335 in words is "five trillion, two hundred fifty-one billion, fifty-four million, three hundred forty-one thousand, three hundred thirty-five".
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