53002111 has 4 divisors (see below), whose sum is σ = 54829800. Its totient is φ = 51174424.

The previous prime is 53002109. The next prime is 53002121. The reversal of 53002111 is 11120035.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 53002111 - 2¹ = 53002109 is a prime.

It is a super-3 number, since 3×53002111³ (a number of 24 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 53002091 and 53002100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53002121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 913801 + ... + 913858.

It is an arithmetic number, because the mean of its divisors is an integer number (13707450).

Almost surely, 2^53002111 is an apocalyptic number.

53002111 is a deficient number, since it is larger than the sum of its proper divisors (1827689).

53002111 is a wasteful number, since it uses less digits than its factorization.

53002111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1827688.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 53002111 is about 7280.2548719121. The cubic root of 53002111 is about 375.6335624749.

Adding to 53002111 its reverse (11120035), we get a palindrome (64122146).

The spelling of 53002111 in words is "fifty-three million, two thousand, one hundred eleven".