53004401 has 2 divisors, whose sum is σ = 53004402. Its totient is φ = 53004400.

The previous prime is 53004311. The next prime is 53004403. The reversal of 53004401 is 10440035.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 41280625 + 11723776 = 6425^2 + 3424^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-53004401 is a prime.

Together with 53004403, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 53004401.

It is not a weakly prime, because it can be changed into another prime (53004403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26502200 + 26502201.

It is an arithmetic number, because the mean of its divisors is an integer number (26502201).

Almost surely, 2^53004401 is an apocalyptic number.

It is an amenable number.

53004401 is a deficient number, since it is larger than the sum of its proper divisors (1).

53004401 is an equidigital number, since it uses as much as digits as its factorization.

53004401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 240, while the sum is 17.

The square root of 53004401 is about 7280.4121449270. The cubic root of 53004401 is about 375.6389722498.

Adding to 53004401 its reverse (10440035), we get a palindrome (63444436).

The spelling of 53004401 in words is "fifty-three million, four thousand, four hundred one".