Base | Representation |
---|---|
bin | 110001010111100001… |
… | …101100101000000000 |
3 | 12001211020000101200000 |
4 | 301113201230220000 |
5 | 1332030030341010 |
6 | 40203534400000 |
7 | 3554406031500 |
oct | 612741545000 |
9 | 161736011600 |
10 | 53008058880 |
11 | 20531738227 |
12 | a334360000 |
13 | 4cca01641a |
14 | 27cc033a00 |
15 | 15a39cb7c0 |
hex | c5786ca00 |
53008058880 has 1440 divisors, whose sum is σ = 232288632576. Its totient is φ = 11537842176.
The previous prime is 53008058879. The next prime is 53008058881. The reversal of 53008058880 is 8885080035.
It is an interprime number because it is at equal distance from previous prime (53008058879) and next prime (53008058881).
It is a tau number, because it is divible by the number of its divisors (1440).
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53008058881) by changing a digit.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 1127831017 + ... + 1127831063.
Almost surely, 253008058880 is an apocalyptic number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53008058880, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (116144316288).
53008058880 is an abundant number, since it is smaller than the sum of its proper divisors (179280573696).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53008058880 is an equidigital number, since it uses as much as digits as its factorization.
53008058880 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 136 (or 101 counting only the distinct ones).
The product of its (nonzero) digits is 307200, while the sum is 45.
The spelling of 53008058880 in words is "fifty-three billion, eight million, fifty-eight thousand, eight hundred eighty".
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