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530103302545350 = 235217793746370241
BaseRepresentation
bin111100010001000000100101…
…1000010101101111111000110
32120111221101021121020102200210
41320202001023002231333012
51023440203030422422400
65115234032325020250
7216441462003605532
oct17042011302557706
92514841247212623
10530103302545350
111439a8603582146
124b5556a3554686
13199a36b08a6401
1494c91cb306bc2
15414430b818950
hex1e2204b0adfc6

530103302545350 has 192 divisors, whose sum is σ = 1409666715555840. Its totient is φ = 131356037529600.

The previous prime is 530103302545307. The next prime is 530103302545357. The reversal of 530103302545350 is 53545203301035.

It is a super-2 number, since 2×5301033025453502 (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 530103302545299 and 530103302545308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (530103302545357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 7546886230 + ... + 7546956470.

It is an arithmetic number, because the mean of its divisors is an integer number (7342014143520).

Almost surely, 2530103302545350 is an apocalyptic number.

530103302545350 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 530103302545350, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (704833357777920).

530103302545350 is an abundant number, since it is smaller than the sum of its proper divisors (879563413010490).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

530103302545350 is a wasteful number, since it uses less digits than its factorization.

530103302545350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107815 (or 107810 counting only the distinct ones).

The product of its (nonzero) digits is 405000, while the sum is 39.

Adding to 530103302545350 its reverse (53545203301035), we get a palindrome (583648505846385).

The spelling of 530103302545350 in words is "five hundred thirty trillion, one hundred three billion, three hundred two million, five hundred forty-five thousand, three hundred fifty".