Base | Representation |
---|---|
bin | 111100010001000011110110… |
… | …0001000101101010010110110 |
3 | 2120111222001100021120212002120 |
4 | 1320202013230020231102312 |
5 | 1023440311343323330304 |
6 | 5115241150541220410 |
7 | 216442130264036301 |
oct | 17042075410552266 |
9 | 2514861307525076 |
10 | 530110300214454 |
11 | 143a00574584553 |
12 | 4b556b16b61706 |
13 | 199a425757440b |
14 | 94c9692817b38 |
15 | 41445bad220d9 |
hex | 1e221ec22d4b6 |
530110300214454 has 16 divisors (see below), whose sum is σ = 1060221772799280. Its totient is φ = 176703238009760.
The previous prime is 530110300214423. The next prime is 530110300214477. The reversal of 530110300214454 is 454412003011035.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42915117 + ... + 53869544.
It is an arithmetic number, because the mean of its divisors is an integer number (66263860799955).
Almost surely, 2530110300214454 is an apocalyptic number.
530110300214454 is an abundant number, since it is smaller than the sum of its proper divisors (530111472584826).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530110300214454 is a wasteful number, since it uses less digits than its factorization.
530110300214454 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97697535.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 530110300214454 its reverse (454412003011035), we get a palindrome (984522303225489).
The spelling of 530110300214454 in words is "five hundred thirty trillion, one hundred ten billion, three hundred million, two hundred fourteen thousand, four hundred fifty-four".
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