Base | Representation |
---|---|
bin | 111100010001000011110110… |
… | …0001000101101010010110111 |
3 | 2120111222001100021120212002121 |
4 | 1320202013230020231102313 |
5 | 1023440311343323330310 |
6 | 5115241150541220411 |
7 | 216442130264036302 |
oct | 17042075410552267 |
9 | 2514861307525077 |
10 | 530110300214455 |
11 | 143a00574584554 |
12 | 4b556b16b61707 |
13 | 199a425757440c |
14 | 94c9692817b39 |
15 | 41445bad220da |
hex | 1e221ec22d4b7 |
530110300214455 has 8 divisors (see below), whose sum is σ = 639361458533952. Its totient is φ = 421935507987168.
The previous prime is 530110300214423. The next prime is 530110300214477. The reversal of 530110300214455 is 554412003011035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 530110300214455 - 25 = 530110300214423 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 530110300214455.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269091521967 + ... + 269091523936.
It is an arithmetic number, because the mean of its divisors is an integer number (79920182316744).
Almost surely, 2530110300214455 is an apocalyptic number.
530110300214455 is a deficient number, since it is larger than the sum of its proper divisors (109251158319497).
530110300214455 is a wasteful number, since it uses less digits than its factorization.
530110300214455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 538183046105.
The product of its (nonzero) digits is 36000, while the sum is 34.
The spelling of 530110300214455 in words is "five hundred thirty trillion, one hundred ten billion, three hundred million, two hundred fourteen thousand, four hundred fifty-five".
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