53015441 has 2 divisors, whose sum is σ = 53015442. Its totient is φ = 53015440.

The previous prime is 53015429. The next prime is 53015449. The reversal of 53015441 is 14451035.

53015441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 39325441 + 13690000 = 6271^2 + 3700^2 .

It is a cyclic number.

It is not a de Polignac number, because 53015441 - 2¹⁰ = 53014417 is a prime.

It is a super-3 number, since 3×53015441³ (a number of 24 digits) contains 333 as substring.

It is equal to p_3170921 and since 53015441 and 3170921 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (53015449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26507720 + 26507721.

It is an arithmetic number, because the mean of its divisors is an integer number (26507721).

Almost surely, 2^53015441 is an apocalyptic number.

It is an amenable number.

53015441 is a deficient number, since it is larger than the sum of its proper divisors (1).

53015441 is an equidigital number, since it uses as much as digits as its factorization.

53015441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1200, while the sum is 23.

The square root of 53015441 is about 7281.1703042849. The cubic root of 53015441 is about 375.6650503759.

Adding to 53015441 its reverse (14451035), we get a palindrome (67466476).

The spelling of 53015441 in words is "fifty-three million, fifteen thousand, four hundred forty-one".