Base | Representation |
---|---|
bin | 110001011000001111… |
… | …000011001100000111 |
3 | 12001212001101102011202 |
4 | 301120033003030013 |
5 | 1332041101312113 |
6 | 40205041253115 |
7 | 3554612056145 |
oct | 613017031407 |
9 | 161761342152 |
10 | 53019947783 |
11 | 20538418570 |
12 | a33833419b |
13 | 4ccc61998a |
14 | 27cd84a595 |
15 | 15a4a79258 |
hex | c583c3307 |
53019947783 has 8 divisors (see below), whose sum is σ = 60354723456. Its totient is φ = 46104302200.
The previous prime is 53019947777. The next prime is 53019947821. The reversal of 53019947783 is 38774991035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53019947783 - 214 = 53019931399 is a prime.
It is a super-2 number, since 2×530199477832 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53019947713) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104782253 + ... + 104782758.
It is an arithmetic number, because the mean of its divisors is an integer number (7544340432).
Almost surely, 253019947783 is an apocalyptic number.
53019947783 is a deficient number, since it is larger than the sum of its proper divisors (7334775673).
53019947783 is a wasteful number, since it uses less digits than its factorization.
53019947783 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 209565045.
The product of its (nonzero) digits is 5715360, while the sum is 56.
The spelling of 53019947783 in words is "fifty-three billion, nineteen million, nine hundred forty-seven thousand, seven hundred eighty-three".
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