Base | Representation |
---|---|
bin | 100110100101001100000… |
… | …0010011110101101000001 |
3 | 200202220210011022101011200 |
4 | 1031022120002132231001 |
5 | 1143334100322231040 |
6 | 15135541535531413 |
7 | 1055044615662420 |
oct | 115123002365501 |
9 | 20686704271150 |
10 | 5302540430145 |
11 | 1764881921602 |
12 | 717802089b69 |
13 | 2c604830987a |
14 | 1449040612b7 |
15 | 92de7e45630 |
hex | 4d29809eb41 |
5302540430145 has 96 divisors (see below), whose sum is σ = 10844033501184. Its totient is φ = 2345583744000.
The previous prime is 5302540430137. The next prime is 5302540430153. The reversal of 5302540430145 is 5410340452035.
5302540430145 is a `hidden beast` number, since 5 + 30 + 2 + 54 + 0 + 430 + 145 = 666.
It is an interprime number because it is at equal distance from previous prime (5302540430137) and next prime (5302540430153).
It is not a de Polignac number, because 5302540430145 - 23 = 5302540430137 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 123027219 + ... + 123070311.
It is an arithmetic number, because the mean of its divisors is an integer number (112958682304).
Almost surely, 25302540430145 is an apocalyptic number.
It is an amenable number.
5302540430145 is an abundant number, since it is smaller than the sum of its proper divisors (5541493071039).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5302540430145 is a wasteful number, since it uses less digits than its factorization.
5302540430145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55743 (or 55740 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 36.
The spelling of 5302540430145 in words is "five trillion, three hundred two billion, five hundred forty million, four hundred thirty thousand, one hundred forty-five".
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