Base | Representation |
---|---|
bin | 11000000111011000000101… |
… | …01001000100101100000111 |
3 | 20221202121201021010011012011 |
4 | 30003230002221010230013 |
5 | 23422320422403302010 |
6 | 304441352003235051 |
7 | 14112201654425533 |
oct | 1403540251045407 |
9 | 227677637104164 |
10 | 53030005525255 |
11 | 159959986a2020 |
12 | 5b456a1678a87 |
13 | 2378928800b45 |
14 | d14947586bc3 |
15 | 61e67371ea8a |
hex | 303b02a44b07 |
53030005525255 has 16 divisors (see below), whose sum is σ = 69836793352704. Its totient is φ = 38336334962080.
The previous prime is 53030005525229. The next prime is 53030005525261. The reversal of 53030005525255 is 55252550003035.
It is a happy number.
It is not a de Polignac number, because 53030005525255 - 211 = 53030005523207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2886763027 + ... + 2886781396.
It is an arithmetic number, because the mean of its divisors is an integer number (4364799584544).
Almost surely, 253030005525255 is an apocalyptic number.
53030005525255 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53030005525255 is a deficient number, since it is larger than the sum of its proper divisors (16806787827449).
53030005525255 is a wasteful number, since it uses less digits than its factorization.
53030005525255 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5773544606.
The product of its (nonzero) digits is 562500, while the sum is 40.
The spelling of 53030005525255 in words is "fifty-three trillion, thirty billion, five million, five hundred twenty-five thousand, two hundred fifty-five".
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