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53032320000 = 21035541131
BaseRepresentation
bin110001011000111110…
…001111110000000000
312001212220122222200000
4301120332033300000
51332102233220000
640210202400000
73555122165562
oct613076176000
9161786588600
1053032320000
11205443a8a40
12a340500000
13500205c20a
1427d134b332
1515a5bc0000
hexc58f8fc00

53032320000 has 1320 divisors, whose sum is σ = 223460869632. Its totient is φ = 12441600000.

The previous prime is 53032319993. The next prime is 53032320017. The reversal of 53032320000 is 2323035.

It is a tau number, because it is divible by the number of its divisors (1320).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 1710719985 + ... + 1710720015.

Almost surely, 253032320000 is an apocalyptic number.

53032320000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 53032320000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (111730434816).

53032320000 is an abundant number, since it is smaller than the sum of its proper divisors (170428549632).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

53032320000 is an equidigital number, since it uses as much as digits as its factorization.

53032320000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97 (or 52 counting only the distinct ones).

The product of its (nonzero) digits is 540, while the sum is 18.

Adding to 53032320000 its reverse (2323035), we get a palindrome (53034643035).

The spelling of 53032320000 in words is "fifty-three billion, thirty-two million, three hundred twenty thousand".