Base | Representation |
---|---|
bin | 1100101001001… |
… | …1100001001011 |
3 | 10200210100122111 |
4 | 3022103201023 |
5 | 102034024120 |
6 | 5132403151 |
7 | 1212526156 |
oct | 312234113 |
9 | 120710574 |
10 | 53033035 |
11 | 27a32560 |
12 | 159164b7 |
13 | acaaac3 |
14 | 7086c9d |
15 | 49c875a |
hex | 329384b |
53033035 has 24 divisors (see below), whose sum is σ = 70876656. Its totient is φ = 37778880.
The previous prime is 53033027. The next prime is 53033039.
It is a happy number.
53033035 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53033035 - 23 = 53033027 is a prime.
It is a super-2 number, since 2×530330352 = 5625005602622450, which contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53032997 and 53033015.
It is not an unprimeable number, because it can be changed into a prime (53033039) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 191317 + ... + 191593.
It is an arithmetic number, because the mean of its divisors is an integer number (2953194).
Almost surely, 253033035 is an apocalyptic number.
53033035 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53033035 is a deficient number, since it is larger than the sum of its proper divisors (17843621).
53033035 is a wasteful number, since it uses less digits than its factorization.
53033035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 411 (or 352 counting only the distinct ones).
The product of its (nonzero) digits is 2025, while the sum is 22.
The square root of 53033035 is about 7282.3783889606. The cubic root of 53033035 is about 375.7066025461.
It can be divided in two parts, 5303 and 3035, that added together give a palindrome (8338).
The spelling of 53033035 in words is "fifty-three million, thirty-three thousand, thirty-five".
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