Base | Representation |
---|---|
bin | 1111011011110101100… |
… | …11010001110100100100 |
3 | 1212200220101121102000212 |
4 | 13231322303101310210 |
5 | 32142114324140400 |
6 | 1043345125154552 |
7 | 53213231106320 |
oct | 7557263216444 |
9 | 1780811542025 |
10 | 530341240100 |
11 | 194a09893241 |
12 | 8694a25ba58 |
13 | 3b01b11ca99 |
14 | 1b950ad8980 |
15 | dbde6b5335 |
hex | 7b7acd1d24 |
530341240100 has 72 divisors (see below), whose sum is σ = 1322513145408. Its totient is φ = 180826646400.
The previous prime is 530341240087. The next prime is 530341240111. The reversal of 530341240100 is 1042143035.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1966202 + ... + 2219601.
Almost surely, 2530341240100 is an apocalyptic number.
530341240100 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
530341240100 is an abundant number, since it is smaller than the sum of its proper divisors (792171905308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
530341240100 is a wasteful number, since it uses less digits than its factorization.
530341240100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4186005 (or 4185998 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 530341240100 its reverse (1042143035), we get a palindrome (531383383135).
The spelling of 530341240100 in words is "five hundred thirty billion, three hundred forty-one million, two hundred forty thousand, one hundred".
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