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5304001 is a prime number
BaseRepresentation
bin10100001110111011000001
3100222110201111
4110032323001
52324212001
6305403321
763040363
oct24167301
910873644
105304001
112aa2a7a
121939541
131139281
149c0d33
156eb851
hex50eec1

5304001 has 2 divisors, whose sum is σ = 5304002. Its totient is φ = 5304000.

The previous prime is 5303999. The next prime is 5304031. The reversal of 5304001 is 1004035.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4665600 + 638401 = 2160^2 + 799^2 .

It is a cyclic number.

It is not a de Polignac number, because 5304001 - 21 = 5303999 is a prime.

Together with 5303999, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5304031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2652000 + 2652001.

It is an arithmetic number, because the mean of its divisors is an integer number (2652001).

Almost surely, 25304001 is an apocalyptic number.

It is an amenable number.

5304001 is a deficient number, since it is larger than the sum of its proper divisors (1).

5304001 is an equidigital number, since it uses as much as digits as its factorization.

5304001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60, while the sum is 13.

The square root of 5304001 is about 2303.0416843818. The cubic root of 5304001 is about 174.3952020290.

Adding to 5304001 its reverse (1004035), we get a palindrome (6308036).

The spelling of 5304001 in words is "five million, three hundred four thousand, one".