53040343 has 4 divisors (see below), whose sum is σ = 55831960. Its totient is φ = 50248728.

The previous prime is 53040341. The next prime is 53040359. The reversal of 53040343 is 34304035.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34304035 = 5 ⋅6860807.

It is a cyclic number.

It is not a de Polignac number, because 53040343 - 2¹ = 53040341 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53040341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1395780 + ... + 1395817.

It is an arithmetic number, because the mean of its divisors is an integer number (13957990).

Almost surely, 2^53040343 is an apocalyptic number.

53040343 is a deficient number, since it is larger than the sum of its proper divisors (2791617).

53040343 is a wasteful number, since it uses less digits than its factorization.

53040343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2791616.

The product of its (nonzero) digits is 2160, while the sum is 22.

The square root of 53040343 is about 7282.8801308274. The cubic root of 53040343 is about 375.7238593229.

Adding to 53040343 its reverse (34304035), we get a palindrome (87344378).

The spelling of 53040343 in words is "fifty-three million, forty thousand, three hundred forty-three".