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530431251350000 = 245571131387587
BaseRepresentation
bin111100010011011001010011…
…0010100001000000111110000
32120120002201202220202211202212
41320212302212110020013300
51024011041200321200000
65120044430342031252
7216504251613501530
oct17046624624100760
92516081686684685
10530431251350000
111440146a3089000
124b5a9168a18528
13199c85b5b39540
1494db01c2ad4c0
15414cb029c9c35
hex1e26ca65081f0

530431251350000 has 960 divisors, whose sum is σ = 1738992231373824. Its totient is φ = 152609846400000.

The previous prime is 530431251349999. The next prime is 530431251350069. The reversal of 530431251350000 is 53152134035.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 6056006207 + ... + 6056093793.

Almost surely, 2530431251350000 is an apocalyptic number.

530431251350000 is a gapful number since it is divisible by the number (50) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 530431251350000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (869496115686912).

530431251350000 is an abundant number, since it is smaller than the sum of its proper divisors (1208560980023824).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

530431251350000 is an equidigital number, since it uses as much as digits as its factorization.

530431251350000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 87673 (or 87625 counting only the distinct ones).

The product of its (nonzero) digits is 27000, while the sum is 32.

The spelling of 530431251350000 in words is "five hundred thirty trillion, four hundred thirty-one billion, two hundred fifty-one million, three hundred fifty thousand".