Base | Representation |
---|---|
bin | 110001011001101100… |
… | …010110000001010111 |
3 | 12001220202101221020002 |
4 | 301121230112001113 |
5 | 1332113331414221 |
6 | 40211313401515 |
7 | 3555326666033 |
oct | 613154260127 |
9 | 161822357202 |
10 | 53044404311 |
11 | 20550202078 |
12 | a34456929b |
13 | 50047006b2 |
14 | 27d2bb51c3 |
15 | 15a6caa80b |
hex | c59b16057 |
53044404311 has 4 divisors (see below), whose sum is σ = 53094972000. Its totient is φ = 52993836624.
The previous prime is 53044404293. The next prime is 53044404317. The reversal of 53044404311 is 11340444035.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53044404311 - 210 = 53044403287 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53044404317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25282271 + ... + 25284368.
It is an arithmetic number, because the mean of its divisors is an integer number (13273743000).
Almost surely, 253044404311 is an apocalyptic number.
53044404311 is a deficient number, since it is larger than the sum of its proper divisors (50567689).
53044404311 is a wasteful number, since it uses less digits than its factorization.
53044404311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50567688.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 53044404311 its reverse (11340444035), we get a palindrome (64384848346).
The spelling of 53044404311 in words is "fifty-three billion, forty-four million, four hundred four thousand, three hundred eleven".
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