Base | Representation |
---|---|
bin | 11000000111111110000100… |
… | …10100110001111001010111 |
3 | 20221211120100200100212101211 |
4 | 30003333002110301321113 |
5 | 23423134210213100210 |
6 | 304455003511402251 |
7 | 14113523253566035 |
oct | 1403770224617127 |
9 | 227746320325354 |
10 | 53050401300055 |
11 | 159a3604570555 |
12 | 5b49634083387 |
13 | 237a82919ab43 |
14 | d15920253555 |
15 | 61ee690b738a |
hex | 303fc2531e57 |
53050401300055 has 8 divisors (see below), whose sum is σ = 64557108061344. Its totient is φ = 41842570039200.
The previous prime is 53050401300053. The next prime is 53050401300109. The reversal of 53050401300055 is 55000310405035.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53050401300055 - 21 = 53050401300053 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53050401300053) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 74718874716 + ... + 74718875425.
It is an arithmetic number, because the mean of its divisors is an integer number (8069638507668).
Almost surely, 253050401300055 is an apocalyptic number.
53050401300055 is a deficient number, since it is larger than the sum of its proper divisors (11506706761289).
53050401300055 is a wasteful number, since it uses less digits than its factorization.
53050401300055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 149437750217.
The product of its (nonzero) digits is 22500, while the sum is 31.
The spelling of 53050401300055 in words is "fifty-three trillion, fifty billion, four hundred one million, three hundred thousand, fifty-five".
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