Base | Representation |
---|---|
bin | 110001011010001001… |
… | …011001010000000001 |
3 | 12001221021201211121000 |
4 | 301122021121100001 |
5 | 1332122304112323 |
6 | 40212144522213 |
7 | 3555451504260 |
oct | 613211312001 |
9 | 161837654530 |
10 | 53052019713 |
11 | 205545336a0 |
12 | a347020369 |
13 | 5006168a54 |
14 | 27d3bd85d7 |
15 | 15a77b1e43 |
hex | c5a259401 |
53052019713 has 64 divisors (see below), whose sum is σ = 98106163200. Its totient is φ = 27526625280.
The previous prime is 53052019711. The next prime is 53052019789. The reversal of 53052019713 is 31791025035.
53052019713 is a `hidden beast` number, since 5 + 30 + 520 + 1 + 97 + 13 = 666.
It is not a de Polignac number, because 53052019713 - 21 = 53052019711 is a prime.
It is not an unprimeable number, because it can be changed into a prime (53052019711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1779393 + ... + 1808961.
It is an arithmetic number, because the mean of its divisors is an integer number (1532908800).
Almost surely, 253052019713 is an apocalyptic number.
It is an amenable number.
53052019713 is a deficient number, since it is larger than the sum of its proper divisors (45054143487).
53052019713 is a wasteful number, since it uses less digits than its factorization.
53052019713 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30459 (or 30453 counting only the distinct ones).
The product of its (nonzero) digits is 28350, while the sum is 36.
The spelling of 53052019713 in words is "fifty-three billion, fifty-two million, nineteen thousand, seven hundred thirteen".
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