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53055099999 = 3211535910101
BaseRepresentation
bin110001011010010101…
…001001010001011111
312001221111112022221200
4301122111021101133
51332124101144444
640212334530543
73555516623556
oct613225112137
9161844468850
1053055099999
1120556247990
12a348066a53
1350069a6ac5
1427d439ad9d
1515a7bbe969
hexc5a54945f

53055099999 has 12 divisors (see below), whose sum is σ = 83601975912. Its totient is φ = 32154606000.

The previous prime is 53055099983. The next prime is 53055100073. The reversal of 53055099999 is 99999055035.

53055099999 is a `hidden beast` number, since 5 + 30 + 5 + 509 + 9 + 9 + 99 = 666.

53055099999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 53055099999 - 24 = 53055099983 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53055099199) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 267954952 + ... + 267955149.

It is an arithmetic number, because the mean of its divisors is an integer number (6966831326).

Almost surely, 253055099999 is an apocalyptic number.

53055099999 is a deficient number, since it is larger than the sum of its proper divisors (30546875913).

53055099999 is a wasteful number, since it uses less digits than its factorization.

53055099999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 535910118 (or 535910115 counting only the distinct ones).

The product of its (nonzero) digits is 22143375, while the sum is 63.

The spelling of 53055099999 in words is "fifty-three billion, fifty-five million, ninety-nine thousand, nine hundred ninety-nine".

Divisors: 1 3 9 11 33 99 535910101 1607730303 4823190909 5895011111 17685033333 53055099999