Base | Representation |
---|---|
bin | 110001011011000011… |
… | …000010111100101011 |
3 | 12001222100011122201211 |
4 | 301123003002330223 |
5 | 1332140141221330 |
6 | 40213444453551 |
7 | 3556024120432 |
oct | 613303027453 |
9 | 161870148654 |
10 | 53067132715 |
11 | 20562016283 |
12 | a3500aa2b7 |
13 | 500932a95c |
14 | 27d5c10119 |
15 | 15a8c99d2a |
hex | c5b0c2f2b |
53067132715 has 64 divisors (see below), whose sum is σ = 69278146560. Its totient is φ = 38898662400.
The previous prime is 53067132709. The next prime is 53067132749. The reversal of 53067132715 is 51723176035.
It is a happy number.
53067132715 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53067132715 - 23 = 53067132707 is a prime.
It is a super-2 number, since 2×530671327152 (a number of 22 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 169543399 + ... + 169543711.
It is an arithmetic number, because the mean of its divisors is an integer number (1082471040).
Almost surely, 253067132715 is an apocalyptic number.
53067132715 is a deficient number, since it is larger than the sum of its proper divisors (16211013845).
53067132715 is a wasteful number, since it uses less digits than its factorization.
53067132715 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 764.
The product of its (nonzero) digits is 132300, while the sum is 40.
The spelling of 53067132715 in words is "fifty-three billion, sixty-seven million, one hundred thirty-two thousand, seven hundred fifteen".
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