Base | Representation |
---|---|
bin | 11000001001011010110111… |
… | …11000011011100101000111 |
3 | 20222000022221210011211010022 |
4 | 30010231123320123211013 |
5 | 23424443223340401020 |
6 | 304533523314245355 |
7 | 14120236002342425 |
oct | 1404553370334507 |
9 | 228008853154108 |
10 | 53100222200135 |
11 | 15a12750126140 |
12 | 5b57218b8685b |
13 | 2382438ac0586 |
14 | d180c8c82115 |
15 | 6213d2d80625 |
hex | 304b5be1b947 |
53100222200135 has 32 divisors (see below), whose sum is σ = 72723531331584. Its totient is φ = 36874806304000.
The previous prime is 53100222200107. The next prime is 53100222200161.
It is a happy number.
53100222200135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53100222200135 - 216 = 53100222134599 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 250402211 + ... + 250614180.
It is an arithmetic number, because the mean of its divisors is an integer number (2272610354112).
Almost surely, 253100222200135 is an apocalyptic number.
53100222200135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53100222200135 is a deficient number, since it is larger than the sum of its proper divisors (19623309131449).
53100222200135 is a wasteful number, since it uses less digits than its factorization.
53100222200135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 501016495.
The product of its (nonzero) digits is 3600, while the sum is 26.
It can be divided in two parts, 5310022 and 2200135, that added together give a palindrome (7510157).
The spelling of 53100222200135 in words is "fifty-three trillion, one hundred billion, two hundred twenty-two million, two hundred thousand, one hundred thirty-five".
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