Base | Representation |
---|---|
bin | 100110101000101011100… |
… | …0100100110000100000110 |
3 | 200210122010211211022211221 |
4 | 1031101113010212010012 |
5 | 1143444430320301014 |
6 | 15143222054150554 |
7 | 1055431515452221 |
oct | 115212704460406 |
9 | 20718124738757 |
10 | 5310040400134 |
11 | 1767a80412008 |
12 | 71915595245a |
13 | 2c6972087032 |
14 | 1450161665b8 |
15 | 931d65bdb24 |
hex | 4d457126106 |
5310040400134 has 8 divisors (see below), whose sum is σ = 7969683391560. Its totient is φ = 2653479269616.
The previous prime is 5310040400113. The next prime is 5310040400173. The reversal of 5310040400134 is 4310040400135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 5310040400099 and 5310040400108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 770460919 + ... + 770467810.
It is an arithmetic number, because the mean of its divisors is an integer number (996210423945).
Almost surely, 25310040400134 is an apocalyptic number.
5310040400134 is a deficient number, since it is larger than the sum of its proper divisors (2659642991426).
5310040400134 is a wasteful number, since it uses less digits than its factorization.
5310040400134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1540930454.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 5310040400134 its reverse (4310040400135), we get a palindrome (9620080800269).
Subtracting from 5310040400134 its reverse (4310040400135), we obtain a palindrome (999999999999).
The spelling of 5310040400134 in words is "five trillion, three hundred ten billion, forty million, four hundred thousand, one hundred thirty-four".
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