Base | Representation |
---|---|
bin | 100110101000101101111… |
… | …1100101110000111100111 |
3 | 200210122100112210022102110 |
4 | 1031101123330232013213 |
5 | 1144000112242101210 |
6 | 15143234140012103 |
7 | 1055433531104130 |
oct | 115213374560747 |
9 | 20718315708373 |
10 | 5310122222055 |
11 | 1768012618032 |
12 | 719179231033 |
13 | 2c6986004781 |
14 | 145022d84c87 |
15 | 931dd882420 |
hex | 4d45bf2e1e7 |
5310122222055 has 32 divisors (see below), whose sum is σ = 9734152163328. Its totient is φ = 2421430848000.
The previous prime is 5310122222047. The next prime is 5310122222063. The reversal of 5310122222055 is 5502222210135.
5310122222055 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (5310122222047) and next prime (5310122222063).
It is not a de Polignac number, because 5310122222055 - 23 = 5310122222047 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 63015991 + ... + 63100200.
It is an arithmetic number, because the mean of its divisors is an integer number (304192255104).
Almost surely, 25310122222055 is an apocalyptic number.
5310122222055 is a deficient number, since it is larger than the sum of its proper divisors (4424029941273).
5310122222055 is a wasteful number, since it uses less digits than its factorization.
5310122222055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 126116607.
The product of its (nonzero) digits is 12000, while the sum is 30.
The spelling of 5310122222055 in words is "five trillion, three hundred ten billion, one hundred twenty-two million, two hundred twenty-two thousand, fifty-five".
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