Base | Representation |
---|---|
bin | 1100101010010… |
… | …0001101111001 |
3 | 10200220211110202 |
4 | 3022210031321 |
5 | 102043221213 |
6 | 5134051545 |
7 | 1213232450 |
oct | 312441571 |
9 | 120824422 |
10 | 53101433 |
11 | 27a79990 |
12 | 15949bb5 |
13 | b002c88 |
14 | 70a3b97 |
15 | 49ddb58 |
hex | 32a4379 |
53101433 has 8 divisors (see below), whose sum is σ = 66204480. Its totient is φ = 41377680.
The previous prime is 53101381. The next prime is 53101463. The reversal of 53101433 is 33410135.
It is a happy number.
53101433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 53101433 - 26 = 53101369 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (53101463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 344738 + ... + 344891.
It is an arithmetic number, because the mean of its divisors is an integer number (8275560).
Almost surely, 253101433 is an apocalyptic number.
It is an amenable number.
53101433 is a deficient number, since it is larger than the sum of its proper divisors (13103047).
53101433 is a wasteful number, since it uses less digits than its factorization.
53101433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 689647.
The product of its (nonzero) digits is 540, while the sum is 20.
The square root of 53101433 is about 7287.0730063586. The cubic root of 53101433 is about 375.8680524833.
Adding to 53101433 its reverse (33410135), we get a palindrome (86511568).
The spelling of 53101433 in words is "fifty-three million, one hundred one thousand, four hundred thirty-three".
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