Base | Representation |
---|---|
bin | 110001011101000111… |
… | …111111010011101101 |
3 | 12002001202202020021112 |
4 | 301131013333103231 |
5 | 1332223101423312 |
6 | 40221131441405 |
7 | 3556626256562 |
oct | 613507772355 |
9 | 162052666245 |
10 | 53101982957 |
11 | 2057a759831 |
12 | a35b8b6265 |
13 | 50136104ba |
14 | 27da6c2869 |
15 | 15abd80d22 |
hex | c5d1ff4ed |
53101982957 has 2 divisors, whose sum is σ = 53101982958. Its totient is φ = 53101982956.
The previous prime is 53101982939. The next prime is 53101982959. The reversal of 53101982957 is 75928910135.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41978272996 + 11123709961 = 204886^2 + 105469^2 .
It is a cyclic number.
It is not a de Polignac number, because 53101982957 - 26 = 53101982893 is a prime.
Together with 53101982959, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (53101982959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26550991478 + 26550991479.
It is an arithmetic number, because the mean of its divisors is an integer number (26550991479).
Almost surely, 253101982957 is an apocalyptic number.
It is an amenable number.
53101982957 is a deficient number, since it is larger than the sum of its proper divisors (1).
53101982957 is an equidigital number, since it uses as much as digits as its factorization.
53101982957 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 680400, while the sum is 50.
The spelling of 53101982957 in words is "fifty-three billion, one hundred one million, nine hundred eighty-two thousand, nine hundred fifty-seven".
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