Base | Representation |
---|---|
bin | 110001011101001100… |
… | …010101101101100100 |
3 | 12002001211220011112110 |
4 | 301131030111231210 |
5 | 1332223344421200 |
6 | 40221212121020 |
7 | 3556642046313 |
oct | 613514255544 |
9 | 162054804473 |
10 | 53103123300 |
11 | 20580368567 |
12 | a360166170 |
13 | 501391c566 |
14 | 27da8dc27a |
15 | 15ac008b50 |
hex | c5d315b64 |
53103123300 has 36 divisors (see below), whose sum is σ = 153645037616. Its totient is φ = 14160832800.
The previous prime is 53103123277. The next prime is 53103123347. The reversal of 53103123300 is 332130135.
53103123300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 88504906 + ... + 88505505.
Almost surely, 253103123300 is an apocalyptic number.
53103123300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
53103123300 is an abundant number, since it is smaller than the sum of its proper divisors (100541914316).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53103123300 is a wasteful number, since it uses less digits than its factorization.
53103123300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 177010428 (or 177010421 counting only the distinct ones).
The product of its (nonzero) digits is 810, while the sum is 21.
Adding to 53103123300 its reverse (332130135), we get a palindrome (53435253435).
The spelling of 53103123300 in words is "fifty-three billion, one hundred three million, one hundred twenty-three thousand, three hundred".
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