53104000001 has 8 divisors (see below), whose sum is σ = 57284087784. Its totient is φ = 48937507200.

The previous prime is 53103999961. The next prime is 53104000003. The reversal of 53104000001 is 10000040135.

53104000001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 16912742401 + 36191257600 = 130049^2 + 190240^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53104000001 - 2¹⁰ = 53103998977 is a prime.

It is a super-2 number, since 2×53104000001² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 53104000001.

It is not an unprimeable number, because it can be changed into a prime (53104000003) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3390626 + ... + 3406251.

It is an arithmetic number, because the mean of its divisors is an integer number (7160510973).

Almost surely, 2^53104000001 is an apocalyptic number.

It is an amenable number.

53104000001 is a deficient number, since it is larger than the sum of its proper divisors (4180087783).

53104000001 is a wasteful number, since it uses less digits than its factorization.

53104000001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6797491.

The product of its (nonzero) digits is 60, while the sum is 14.

Adding to 53104000001 its reverse (10000040135), we get a palindrome (63104040136).

The spelling of 53104000001 in words is "fifty-three billion, one hundred four million, one", and thus it is an aban number.