Base | Representation |
---|---|
bin | 11000001001110001011100… |
… | …11010101001110001101111 |
3 | 20222001111020121002100222202 |
4 | 30010320232122221301233 |
5 | 23430143040121234020 |
6 | 304543250225332115 |
7 | 14121145255563161 |
oct | 1404705632516157 |
9 | 228044217070882 |
10 | 53112344321135 |
11 | 15a17900808060 |
12 | 5b5964079703b |
13 | 238361b342538 |
14 | d18918bac931 |
15 | 6218921c4e75 |
hex | 304e2e6a9c6f |
53112344321135 has 16 divisors (see below), whose sum is σ = 70245679768992. Its totient is φ = 38228941363200.
The previous prime is 53112344321119. The next prime is 53112344321191.
It is a happy number.
53112344321135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53112344321135 - 24 = 53112344321119 is a prime.
It is a super-2 number, since 2×531123443211352 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4977721406 + ... + 4977732075.
It is an arithmetic number, because the mean of its divisors is an integer number (4390354985562).
Almost surely, 253112344321135 is an apocalyptic number.
53112344321135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53112344321135 is a deficient number, since it is larger than the sum of its proper divisors (17133335447857).
53112344321135 is a wasteful number, since it uses less digits than its factorization.
53112344321135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9955453594.
The product of its digits is 129600, while the sum is 38.
It can be divided in two parts, 5311234 and 4321135, that added together give a palindrome (9632369).
The spelling of 53112344321135 in words is "fifty-three trillion, one hundred twelve billion, three hundred forty-four million, three hundred twenty-one thousand, one hundred thirty-five".
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