Base | Representation |
---|---|
bin | 1100101010100… |
… | …0110001100111 |
3 | 10200221210002020 |
4 | 3022220301213 |
5 | 102044320403 |
6 | 5134314223 |
7 | 1213341051 |
oct | 312506147 |
9 | 120853066 |
10 | 53120103 |
11 | 27a91a13 |
12 | 15958973 |
13 | b00b61a |
14 | 70aa8d1 |
15 | 49e4453 |
hex | 32a8c67 |
53120103 has 4 divisors (see below), whose sum is σ = 70826808. Its totient is φ = 35413400.
The previous prime is 53120099. The next prime is 53120117. The reversal of 53120103 is 30102135.
It is a happy number.
53120103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 53120103 - 22 = 53120099 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53120173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8853348 + ... + 8853353.
It is an arithmetic number, because the mean of its divisors is an integer number (17706702).
Almost surely, 253120103 is an apocalyptic number.
53120103 is a deficient number, since it is larger than the sum of its proper divisors (17706705).
53120103 is a wasteful number, since it uses less digits than its factorization.
53120103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17706704.
The product of its (nonzero) digits is 90, while the sum is 15.
The square root of 53120103 is about 7288.3539293863. The cubic root of 53120103 is about 375.9120979631.
Adding to 53120103 its reverse (30102135), we get a palindrome (83222238).
The spelling of 53120103 in words is "fifty-three million, one hundred twenty thousand, one hundred three".
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