Base | Representation |
---|---|
bin | 11000001010000111101111… |
… | …01101001101110000110111 |
3 | 20222002122010121011000122202 |
4 | 30011003313231031300313 |
5 | 23430342042200422020 |
6 | 304552545520215115 |
7 | 14122050646563215 |
oct | 1405036755156067 |
9 | 228078117130582 |
10 | 53124311342135 |
11 | 15a21991894060 |
12 | 5b5ba2046a49b |
13 | 23847a76cb157 |
14 | d19332283cb5 |
15 | 621d42acde75 |
hex | 3050f7b4dc37 |
53124311342135 has 16 divisors (see below), whose sum is σ = 69598505452320. Its totient is φ = 38605889226240.
The previous prime is 53124311342059. The next prime is 53124311342149.
It is a happy number.
53124311342135 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 53124311342135 - 238 = 52849433435191 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 374598062 + ... + 374739851.
It is an arithmetic number, because the mean of its divisors is an integer number (4349906590770).
Almost surely, 253124311342135 is an apocalyptic number.
53124311342135 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
53124311342135 is a deficient number, since it is larger than the sum of its proper divisors (16474194110185).
53124311342135 is a wasteful number, since it uses less digits than its factorization.
53124311342135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 749339218.
The product of its digits is 129600, while the sum is 38.
It can be divided in two parts, 5312431 and 1342135, that added together give a palindrome (6654566).
The spelling of 53124311342135 in words is "fifty-three trillion, one hundred twenty-four billion, three hundred eleven million, three hundred forty-two thousand, one hundred thirty-five".
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