Base | Representation |
---|---|
bin | 1111011101100111001… |
… | …10010101100111001110 |
3 | 1212210100210200012101200 |
4 | 13232303212111213032 |
5 | 32201042300232240 |
6 | 1044023445250330 |
7 | 53245651516506 |
oct | 7566346254716 |
9 | 1783323605350 |
10 | 531294149070 |
11 | 195358772913 |
12 | 86b754039a6 |
13 | 3b14067c949 |
14 | 1ba014a8a06 |
15 | dc48193930 |
hex | 7bb39959ce |
531294149070 has 48 divisors (see below), whose sum is σ = 1381462093440. Its totient is φ = 141668459712.
The previous prime is 531294149059. The next prime is 531294149083. The reversal of 531294149070 is 70941492135.
531294149070 is a `hidden beast` number, since 5 + 3 + 1 + 2 + 94 + 1 + 490 + 70 = 666.
It is a super-3 number, since 3×5312941490703 (a number of 36 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (45).
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1123971 + ... + 1525089.
It is an arithmetic number, because the mean of its divisors is an integer number (28780460280).
Almost surely, 2531294149070 is an apocalyptic number.
531294149070 is an abundant number, since it is smaller than the sum of its proper divisors (850167944370).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
531294149070 is a wasteful number, since it uses less digits than its factorization.
531294149070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 415849 (or 415846 counting only the distinct ones).
The product of its (nonzero) digits is 272160, while the sum is 45.
The spelling of 531294149070 in words is "five hundred thirty-one billion, two hundred ninety-four million, one hundred forty-nine thousand, seventy".
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