Base | Representation |
---|---|
bin | 100110101010001000111… |
… | …0011011011111000111101 |
3 | 200210221020011211011011010 |
4 | 1031110101303123320331 |
5 | 1144022334322211110 |
6 | 15144501005545433 |
7 | 1055602246251231 |
oct | 115242163337075 |
9 | 20727204734133 |
10 | 5313173241405 |
11 | 1769338865027 |
12 | 71988ab75279 |
13 | 2c7051140373 |
14 | 14523226c5c1 |
15 | 9331b653020 |
hex | 4d511cdbe3d |
5313173241405 has 32 divisors (see below), whose sum is σ = 8871674745600. Its totient is φ = 2710187251200.
The previous prime is 5313173241353. The next prime is 5313173241407. The reversal of 5313173241405 is 5041423713135.
It is not a de Polignac number, because 5313173241405 - 219 = 5313172717117 is a prime.
It is a super-2 number, since 2×53131732414052 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5313173241407) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2270955 + ... + 3972855.
It is an arithmetic number, because the mean of its divisors is an integer number (277239835800).
Almost surely, 25313173241405 is an apocalyptic number.
It is an amenable number.
5313173241405 is a deficient number, since it is larger than the sum of its proper divisors (3558501504195).
5313173241405 is a wasteful number, since it uses less digits than its factorization.
5313173241405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1710981.
The product of its (nonzero) digits is 151200, while the sum is 39.
The spelling of 5313173241405 in words is "five trillion, three hundred thirteen billion, one hundred seventy-three million, two hundred forty-one thousand, four hundred five".
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