53140493 has 4 divisors (see below), whose sum is σ = 60732000. Its totient is φ = 45548988.

The previous prime is 53140471. The next prime is 53140517. The reversal of 53140493 is 39404135.

53140493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39404135 = 5 ⋅7880827.

It is a cyclic number.

It is not a de Polignac number, because 53140493 - 2⁶ = 53140429 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (53140463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3795743 + ... + 3795756.

It is an arithmetic number, because the mean of its divisors is an integer number (15183000).

Almost surely, 2^53140493 is an apocalyptic number.

It is an amenable number.

53140493 is a deficient number, since it is larger than the sum of its proper divisors (7591507).

53140493 is an equidigital number, since it uses as much as digits as its factorization.

53140493 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7591506.

The product of its (nonzero) digits is 6480, while the sum is 29.

The square root of 53140493 is about 7289.7526021121. The cubic root of 53140493 is about 375.9601894058.

The spelling of 53140493 in words is "fifty-three million, one hundred forty thousand, four hundred ninety-three".