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53142024135 = 353542801609
BaseRepresentation
bin110001011111100000…
…101110111111000111
312002011120002112110010
4301133200232333013
51332313324233020
640225122001303
73560623515654
oct613740567707
9162146075403
1053142024135
11205a0318312
12a3711a6233
13501b9bc9c5
142801b46c2b
1515b063ede0
hexc5f82efc7

53142024135 has 8 divisors (see below), whose sum is σ = 85027238640. Its totient is φ = 28342412864.

The previous prime is 53142024127. The next prime is 53142024203.

53142024135 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 53142024135 - 23 = 53142024127 is a prime.

It is a super-3 number, since 3×531420241353 (a number of 33 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1771400790 + ... + 1771400819.

It is an arithmetic number, because the mean of its divisors is an integer number (10628404830).

Almost surely, 253142024135 is an apocalyptic number.

53142024135 is a deficient number, since it is larger than the sum of its proper divisors (31885214505).

53142024135 is a wasteful number, since it uses less digits than its factorization.

53142024135 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3542801617.

The product of its (nonzero) digits is 14400, while the sum is 30.

It can be divided in two parts, 531420 and 24135, that added together give a palindrome (555555).

The spelling of 53142024135 in words is "fifty-three billion, one hundred forty-two million, twenty-four thousand, one hundred thirty-five".

Divisors: 1 3 5 15 3542801609 10628404827 17714008045 53142024135