531540131 has 2 divisors, whose sum is σ = 531540132. Its totient is φ = 531540130.

The previous prime is 531540091. The next prime is 531540133. The reversal of 531540131 is 131045135.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 531540131 - 2¹⁴ = 531523747 is a prime.

It is a super-2 number, since 2×531540131² = 565069821726994322, which contains 22 as substring.

Together with 531540133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 531540097 and 531540106.

It is not a weakly prime, because it can be changed into another prime (531540133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 265770065 + 265770066.

It is an arithmetic number, because the mean of its divisors is an integer number (265770066).

Almost surely, 2^531540131 is an apocalyptic number.

531540131 is a deficient number, since it is larger than the sum of its proper divisors (1).

531540131 is an equidigital number, since it uses as much as digits as its factorization.

531540131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 531540131 is about 23055.1541092225. The cubic root of 531540131 is about 810.0503606345.

Adding to 531540131 its reverse (131045135), we get a palindrome (662585266).

The spelling of 531540131 in words is "five hundred thirty-one million, five hundred forty thousand, one hundred thirty-one".