Base | Representation |
---|---|
bin | 100110101101011001100… |
… | …0111111011011001010111 |
3 | 200211121022010022201202221 |
4 | 1031122303013323121113 |
5 | 1144131204211244112 |
6 | 15152015435443211 |
7 | 1056240613625152 |
oct | 115326307733127 |
9 | 20747263281687 |
10 | 5320174712407 |
11 | 1771300a238a5 |
12 | 71b1038b6507 |
13 | 2c78c883ca09 |
14 | 1456d808cc99 |
15 | 935cb15ce07 |
hex | 4d6b31fb657 |
5320174712407 has 16 divisors (see below), whose sum is σ = 5646476639232. Its totient is φ = 4995367021440.
The previous prime is 5320174712401. The next prime is 5320174712443. The reversal of 5320174712407 is 7042174710235.
It is a cyclic number.
It is not a de Polignac number, because 5320174712407 - 211 = 5320174710359 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5320174712401) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 15624858 + ... + 15961720.
It is an arithmetic number, because the mean of its divisors is an integer number (352904789952).
Almost surely, 25320174712407 is an apocalyptic number.
5320174712407 is a deficient number, since it is larger than the sum of its proper divisors (326301926825).
5320174712407 is a wasteful number, since it uses less digits than its factorization.
5320174712407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 339078.
The product of its (nonzero) digits is 329280, while the sum is 43.
The spelling of 5320174712407 in words is "five trillion, three hundred twenty billion, one hundred seventy-four million, seven hundred twelve thousand, four hundred seven".
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