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5325141130069 is a prime number
BaseRepresentation
bin100110101111101101100…
…1001010011101101010101
3200212002010020111220000211
41031133123021103231111
51144221342112130234
615154200331205421
71056504650524015
oct115373311235525
920762106456024
105325141130069
11177341a383a02
1272006aba6871
132c820a740ba7
14145a498cbc45
15937bc17e164
hex4d7db253b55

5325141130069 has 2 divisors, whose sum is σ = 5325141130070. Its totient is φ = 5325141130068.

The previous prime is 5325141130019. The next prime is 5325141130097. The reversal of 5325141130069 is 9600311415235.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4637618241169 + 687522888900 = 2153513^2 + 829170^2 .

It is a cyclic number.

It is not a de Polignac number, because 5325141130069 - 217 = 5325140998997 is a prime.

It is a super-2 number, since 2×53251411300692 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5325141130019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662570565034 + 2662570565035.

It is an arithmetic number, because the mean of its divisors is an integer number (2662570565035).

Almost surely, 25325141130069 is an apocalyptic number.

It is an amenable number.

5325141130069 is a deficient number, since it is larger than the sum of its proper divisors (1).

5325141130069 is an equidigital number, since it uses as much as digits as its factorization.

5325141130069 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 40.

The spelling of 5325141130069 in words is "five trillion, three hundred twenty-five billion, one hundred forty-one million, one hundred thirty thousand, sixty-nine".