Base | Representation |
---|---|
bin | 110001101000111011… |
… | …011010110111010111 |
3 | 12002120120101021120000 |
4 | 301220323122313113 |
5 | 1333124300431201 |
6 | 40252524142343 |
7 | 3564552435300 |
oct | 615073326727 |
9 | 162516337500 |
10 | 53300014551 |
11 | 20671517903 |
12 | a3b60979b3 |
13 | 5045658864 |
14 | 2818b117a7 |
15 | 15be44bd86 |
hex | c68edadd7 |
53300014551 has 60 divisors (see below), whose sum is σ = 96647495472. Its totient is φ = 29132877312.
The previous prime is 53300014511. The next prime is 53300014567. The reversal of 53300014551 is 15541000335.
It is not a de Polignac number, because 53300014551 - 223 = 53291625943 is a prime.
It is a super-2 number, since 2×533000145512 (a number of 22 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53300014511) by changing a digit.
It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 200650 + ... + 383223.
Almost surely, 253300014551 is an apocalyptic number.
53300014551 is a deficient number, since it is larger than the sum of its proper divisors (43347480921).
53300014551 is a wasteful number, since it uses less digits than its factorization.
53300014551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 583922 (or 583906 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 27.
Adding to 53300014551 its reverse (15541000335), we get a palindrome (68841014886).
The spelling of 53300014551 in words is "fifty-three billion, three hundred million, fourteen thousand, five hundred fifty-one".
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