Base | Representation |
---|---|
bin | 100110110010000001011… |
… | …1010111100100110010111 |
3 | 200212112221001221101221020 |
4 | 1031210002322330212113 |
5 | 1144312022433440320 |
6 | 15200340554252223 |
7 | 1060041634355340 |
oct | 115440272744627 |
9 | 20775831841836 |
10 | 5330103421335 |
11 | 1775536475870 |
12 | 721014a27073 |
13 | 2c881b828b04 |
14 | 145d9a9750c7 |
15 | 939acb37940 |
hex | 4d902ebc997 |
5330103421335 has 64 divisors (see below), whose sum is σ = 10639056789504. Its totient is φ = 2213745667200.
The previous prime is 5330103421327. The next prime is 5330103421339. The reversal of 5330103421335 is 5331243010335.
It is not a de Polignac number, because 5330103421335 - 23 = 5330103421327 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 5330103421296 and 5330103421305.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5330103421339) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 460990 + ... + 3297380.
It is an arithmetic number, because the mean of its divisors is an integer number (166235262336).
Almost surely, 25330103421335 is an apocalyptic number.
5330103421335 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5330103421335 is a deficient number, since it is larger than the sum of its proper divisors (5308953368169).
5330103421335 is a wasteful number, since it uses less digits than its factorization.
5330103421335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2838044.
The product of its (nonzero) digits is 48600, while the sum is 33.
The spelling of 5330103421335 in words is "five trillion, three hundred thirty billion, one hundred three million, four hundred twenty-one thousand, three hundred thirty-five".
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