Base | Representation |
---|---|
bin | 1111100000110110101… |
… | …11001010000011110111 |
3 | 1212221212010101121000002 |
4 | 13300123113022003313 |
5 | 32213123430000210 |
6 | 1044512313541515 |
7 | 53340050513015 |
oct | 7603327120367 |
9 | 1787763347002 |
10 | 533035000055 |
11 | 1960713a7a38 |
12 | 8738041489b |
13 | 3b35a23019c |
14 | 1bb287858b5 |
15 | dceae164a5 |
hex | 7c1b5ca0f7 |
533035000055 has 16 divisors (see below), whose sum is σ = 667646539200. Its totient is φ = 407769086208.
The previous prime is 533035000039. The next prime is 533035000067. The reversal of 533035000055 is 550000530335.
It is a cyclic number.
It is not a de Polignac number, because 533035000055 - 24 = 533035000039 is a prime.
It is a super-2 number, since 2×5330350000552 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 533034999991 and 533035000027.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 275312 + ... + 1068581.
It is an arithmetic number, because the mean of its divisors is an integer number (41727908700).
Almost surely, 2533035000055 is an apocalyptic number.
533035000055 is a deficient number, since it is larger than the sum of its proper divisors (134611539145).
533035000055 is a wasteful number, since it uses less digits than its factorization.
533035000055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1347370.
The product of its (nonzero) digits is 16875, while the sum is 29.
The spelling of 533035000055 in words is "five hundred thirty-three billion, thirty-five million, fifty-five", and thus it is an aban number.
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