Base | Representation |
---|---|
bin | 11000010000100001000001… |
… | …11100001000101001100100 |
3 | 20222212122022022112010111020 |
4 | 30020100200330020221210 |
5 | 23442442101342420200 |
6 | 305241525554211140 |
7 | 14143660125312513 |
oct | 1410204074105144 |
9 | 228778268463436 |
10 | 53344046451300 |
11 | 15aa70a05aa930 |
12 | 5b96525283ab0 |
13 | 239c42556a7c7 |
14 | d25c193b667a |
15 | 6279038e7ea0 |
hex | 308420f08a64 |
53344046451300 has 144 divisors (see below), whose sum is σ = 168415311896832. Its totient is φ = 12928656297600.
The previous prime is 53344046451277. The next prime is 53344046451301. The reversal of 53344046451300 is 315464044335.
It is not an unprimeable number, because it can be changed into a prime (53344046451301) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11190807 + ... + 15228993.
Almost surely, 253344046451300 is an apocalyptic number.
53344046451300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 53344046451300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (84207655948416).
53344046451300 is an abundant number, since it is smaller than the sum of its proper divisors (115071265445532).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53344046451300 is a wasteful number, since it uses less digits than its factorization.
53344046451300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4042218 (or 4042211 counting only the distinct ones).
The product of its (nonzero) digits is 1036800, while the sum is 42.
The spelling of 53344046451300 in words is "fifty-three trillion, three hundred forty-four billion, forty-six million, four hundred fifty-one thousand, three hundred".
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