Base | Representation |
---|---|
bin | 110001101011100111… |
… | …100100011001001001 |
3 | 12002200201022000020210 |
4 | 301223213210121021 |
5 | 1333222324023340 |
6 | 40301215311333 |
7 | 3565641141225 |
oct | 615347443111 |
9 | 162621260223 |
10 | 53345142345 |
11 | 20694a40000 |
12 | a40921b549 |
13 | 5051ac93b1 |
14 | 2820adb785 |
15 | 15c33b3180 |
hex | c6b9e4649 |
53345142345 has 160 divisors (see below), whose sum is σ = 100185984000. Its totient is φ = 24184589440.
The previous prime is 53345142341. The next prime is 53345142421. The reversal of 53345142345 is 54324154335.
53345142345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 53345142345 - 22 = 53345142341 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (53345142341) by changing a digit.
It is a polite number, since it can be written in 159 ways as a sum of consecutive naturals, for example, 298017466 + ... + 298017644.
It is an arithmetic number, because the mean of its divisors is an integer number (626162400).
Almost surely, 253345142345 is an apocalyptic number.
53345142345 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
53345142345 is a deficient number, since it is larger than the sum of its proper divisors (46840841655).
53345142345 is a wasteful number, since it uses less digits than its factorization.
53345142345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 313 (or 280 counting only the distinct ones).
The product of its digits is 432000, while the sum is 39.
The spelling of 53345142345 in words is "fifty-three billion, three hundred forty-five million, one hundred forty-two thousand, three hundred forty-five".
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