Base | Representation |
---|---|
bin | 110001101100000110… |
… | …000101001100111101 |
3 | 12002201021100101102020 |
4 | 301230012011030331 |
5 | 1333231401003203 |
6 | 40302102550353 |
7 | 3566066134122 |
oct | 615406051475 |
9 | 162637311366 |
10 | 53353141053 |
11 | 20699503603 |
12 | a40ba383b9 |
13 | 505366a064 |
14 | 2821bc0749 |
15 | 15c3e43153 |
hex | c6c18533d |
53353141053 has 4 divisors (see below), whose sum is σ = 71137521408. Its totient is φ = 35568760700.
The previous prime is 53353141001. The next prime is 53353141057. The reversal of 53353141053 is 35014135335.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 53353141053 - 233 = 44763206461 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (53353141057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8892190173 + ... + 8892190178.
It is an arithmetic number, because the mean of its divisors is an integer number (17784380352).
Almost surely, 253353141053 is an apocalyptic number.
It is an amenable number.
53353141053 is a deficient number, since it is larger than the sum of its proper divisors (17784380355).
53353141053 is a wasteful number, since it uses less digits than its factorization.
53353141053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17784380354.
The product of its (nonzero) digits is 40500, while the sum is 33.
Adding to 53353141053 its reverse (35014135335), we get a palindrome (88367276388).
The spelling of 53353141053 in words is "fifty-three billion, three hundred fifty-three million, one hundred forty-one thousand, fifty-three".
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