Base | Representation |
---|---|
bin | 100110111000101110100… |
… | …0011000100110101010111 |
3 | 200220221002102101212201111 |
4 | 1031301131003010311113 |
5 | 1200031014100403133 |
6 | 15211121331435451 |
7 | 1061061462606400 |
oct | 115613503046527 |
9 | 20827072355644 |
10 | 5344500403543 |
11 | 1780654168674 |
12 | 723972455b87 |
13 | 2c9ca44607b2 |
14 | 146964a689a7 |
15 | 94051a351cd |
hex | 4dc5d0c4d57 |
5344500403543 has 24 divisors (see below), whose sum is σ = 6609008491344. Its totient is φ = 4294352160000.
The previous prime is 5344500403483. The next prime is 5344500403547. The reversal of 5344500403543 is 3453040054435.
It is not a de Polignac number, because 5344500403543 - 217 = 5344500272471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5344500403496 and 5344500403505.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5344500403547) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 12571728 + ... + 12989893.
It is an arithmetic number, because the mean of its divisors is an integer number (275375353806).
Almost surely, 25344500403543 is an apocalyptic number.
5344500403543 is a deficient number, since it is larger than the sum of its proper divisors (1264508087801).
5344500403543 is a wasteful number, since it uses less digits than its factorization.
5344500403543 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25561903 (or 25561896 counting only the distinct ones).
The product of its (nonzero) digits is 864000, while the sum is 40.
Adding to 5344500403543 its reverse (3453040054435), we get a palindrome (8797540457978).
The spelling of 5344500403543 in words is "five trillion, three hundred forty-four billion, five hundred million, four hundred three thousand, five hundred forty-three".
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