Base | Representation |
---|---|
bin | 100110111000110110100… |
… | …0001000001100110011111 |
3 | 200220221210002111111120222 |
4 | 1031301231001001212133 |
5 | 1200032041141121341 |
6 | 15211204101431555 |
7 | 1061101224654044 |
oct | 115615501014637 |
9 | 20827702444528 |
10 | 5344768301471 |
11 | 1780781406315 |
12 | 723a2810b5bb |
13 | 2ca017acb891 |
14 | 14698c4831cb |
15 | 9406a30244b |
hex | 4dc6d04199f |
5344768301471 has 2 divisors, whose sum is σ = 5344768301472. Its totient is φ = 5344768301470.
The previous prime is 5344768301347. The next prime is 5344768301473. The reversal of 5344768301471 is 1741038674435.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5344768301471 - 210 = 5344768300447 is a prime.
It is a super-3 number, since 3×53447683014713 (a number of 39 digits) contains 333 as substring.
Together with 5344768301473, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5344768301473) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2672384150735 + 2672384150736.
It is an arithmetic number, because the mean of its divisors is an integer number (2672384150736).
Almost surely, 25344768301471 is an apocalyptic number.
5344768301471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5344768301471 is an equidigital number, since it uses as much as digits as its factorization.
5344768301471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6773760, while the sum is 53.
The spelling of 5344768301471 in words is "five trillion, three hundred forty-four billion, seven hundred sixty-eight million, three hundred one thousand, four hundred seventy-one".
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